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Lesson 6.4 - Finding Zeros, Relative Min, Relative Max (Graphing Calculator - Guided Example 1) - YouTube
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Pre-Calculus - How to find the maximum or minimum of a function using a calculator (Ti-83/84) - YouTube
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How to Find the Maximum Value of a Function | Practice & Overview - Video & Lesson Transcript | Study.com
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MAXIMA MINIMA CALCULATOR TECHNIQUE DIFFERENTIAL CALCULUS 1st method + CALCULATOR TECHNIQUE PLAYLIST - YouTube
![SOLVED: (Maxima and Minima) Find the absolute maximum and absolute minimum values of f on the given interval. (Hint: Use a calculator for comparing values) [2 pts] (a) f (x) [0, 3] SOLVED: (Maxima and Minima) Find the absolute maximum and absolute minimum values of f on the given interval. (Hint: Use a calculator for comparing values) [2 pts] (a) f (x) [0, 3]](https://cdn.numerade.com/ask_images/c50be3e4e5a44c12a56fc1a46e5ff5ae.jpg)
SOLVED: (Maxima and Minima) Find the absolute maximum and absolute minimum values of f on the given interval. (Hint: Use a calculator for comparing values) [2 pts] (a) f (x) [0, 3]
![SOLVED:Use a graphing calculator to estimate the x -coordinates at which the maxima and minima of each function occur. Round to the nearest hundredth. f(x)=-x^3+6 x^2-6 x-5 SOLVED:Use a graphing calculator to estimate the x -coordinates at which the maxima and minima of each function occur. Round to the nearest hundredth. f(x)=-x^3+6 x^2-6 x-5](https://cdn.numerade.com/previews/b71ffa8d-a85a-49af-9446-4f4783fd5ace.gif)
SOLVED:Use a graphing calculator to estimate the x -coordinates at which the maxima and minima of each function occur. Round to the nearest hundredth. f(x)=-x^3+6 x^2-6 x-5
![Use a graphing calculator to estimate the absolute maximum and absolute minimum values of the function, accurate to three decimal places. p(t) = \sqrt3{t^2 - t - 1},-1 \leq t \leq 3 Use a graphing calculator to estimate the absolute maximum and absolute minimum values of the function, accurate to three decimal places. p(t) = \sqrt3{t^2 - t - 1},-1 \leq t \leq 3](https://homework.study.com/cimages/multimages/16/graph6746881644093163929.png)
Use a graphing calculator to estimate the absolute maximum and absolute minimum values of the function, accurate to three decimal places. p(t) = \sqrt3{t^2 - t - 1},-1 \leq t \leq 3
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